Notice that we had to differentiate twice, not to mention that we had to first solve for {{MATH_60}} in terms of {{MATH_61}} in order to compute these two slopes. {{CMD_62}} {{CMD_63}} {{CMD_64}} Let's take a different approach, namely let's use implicit differentiation. {{CMD_65}} Consider the curve (a circle) defined by: {{MATH_66}} {{CMD_67}} {{CMD_68}} Compute {{MATH_69}}. {{CMD_70}} Find the slope of the line tangent to the circle at {{MATH_71}}. {{CMD_72}} Find the slope of the line tangent to the circle at {{MATH_73}}. {{CMD_74}} {{CMD_75}}