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Seja \(s(t) = t^3 - 2t^2\). O gráfico de \(s\) é dado abaixo.
Suponha que \(A\) e \(B\) sejam dois pontos no gráfico de \(s\). Preencha as lacunas.
\begin{align*} A &= \left (2,\class{xm-answer}{\cssId{xm-answer-1}{\phantom{\rule{7em}{1.5em}}}}\right )\\ B &= \left (1,\class{xm-answer}{\cssId{xm-answer-2}{\phantom{\rule{7em}{1.5em}}}}\right ) \end{align*}
Marcamos \(A\) e \(B\) no gráfico de \(s\) abaixo.
A inclinação da reta secante entre \(A\) e \(B\) é \(\class{xm-answer}{\cssId{xm-answer-3}{\phantom{\rule{7em}{1.5em}}}}\).
Desenhamos a reta secante entre \(A\) e \(B\) e também a reta tangente a \(s\) em \(A\).
Com base no desenho da reta tangente, um bom número inteiro para estimar a
inclinação da reta tangente é \(\class{xm-answer}{\cssId{xm-answer-4}{\phantom{\rule{7em}{1.5em}}}}\)
Suponha que a função \(s(t) = t^3 - 2t^2\) represente a posição, no instante \(t\), de um objeto que se move
ao longo de uma reta, em que \(s\) é medida em pés e \(t\) é medido em segundos. A
velocidade média do objeto no intervalo de tempo \(\left [1,2\right ]\) é \(\class{xm-answer}{\cssId{xm-answer-5}{\phantom{\rule{7em}{1.5em}}}}\)\(ft/s\).
Complete a tabela a seguir com as velocidades médias apropriadas (em \(ft/s\)),
arredondadas para duas casas decimais.
\[ \begin{array}{|c|c|c|c|c|c|} \hline \text {Time interval} & \left [1,2\right ] & \left [1.5,2\right ] & \left [1.9,2\right ] & \left [2,2.1\right ] & \left [2,2.01\right ]\\\hline \text {Average velocity} & \class{xm-answer}{\cssId{xm-answer-6}{\phantom{\rule{7em}{1.5em}}}} & \class{xm-answer}{\cssId{xm-answer-7}{\phantom{\rule{7em}{1.5em}}}} & \class{xm-answer}{\cssId{xm-answer-8}{\phantom{\rule{7em}{1.5em}}}} & \class{xm-answer}{\cssId{xm-answer-9}{\phantom{\rule{7em}{1.5em}}}} & \class{xm-answer}{\cssId{xm-answer-10}{\phantom{\rule{7em}{1.5em}}}} \\\hline \end{array} \]
Um bom número inteiro para estimar a velocidade instantânea do objeto no instante \(t= 2\)
é \(\class{xm-answer}{\cssId{xm-answer-11}{\phantom{\rule{7em}{1.5em}}}}\)\((ft/s)\).
Usando limites, calcule a velocidade instantânea do objeto no instante \(t=2\).
\[ v(2) = \lim _{t\to 2}\frac {s(t)-s(2)}{ \class{xm-answer}{\cssId{xm-answer-12}{\phantom{\rule{7em}{1.5em}}}}} = \lim _{t\to 2}\frac { \class{xm-answer}{\cssId{xm-answer-13}{\phantom{\rule{7em}{1.5em}}}} -\class{xm-answer}{\cssId{xm-answer-14}{\phantom{\rule{7em}{1.5em}}}}}{\class{xm-answer}{\cssId{xm-answer-15}{\phantom{\rule{7em}{1.5em}}}}} = \lim _{t\to 2}\frac { t^2\Bigl (\class{xm-answer}{\cssId{xm-answer-16}{\phantom{\rule{7em}{1.5em}}}}\Bigr )} {\class{xm-answer}{\cssId{xm-answer-17}{\phantom{\rule{7em}{1.5em}}}}} = \lim _{t\to 2}\class{xm-answer}{\cssId{xm-answer-18}{\phantom{\rule{7em}{1.5em}}}}=\class{xm-answer}{\cssId{xm-answer-19}{\phantom{\rule{7em}{1.5em}}}}\text {pés/s.} \]