The curve defined by the equation {{MATH_37}} is not a graph of a function. If we solve for {{MATH_38}}, we obtain two solutions: {{MATH_39}} and {{MATH_40}}. The point {{MATH_41}} lies on the graph of the function {{MATH_42}}. Let's compute the derivative of {{MATH_43}}. {{MATH_44}} Therefore, the slope of the tangent line at the point {{MATH_45}} is given by {{MATH_46}} {{CMD_47}} {{CMD_48}} Find the slope of the line tangent to the circle at the point {{MATH_49}}.