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Você tem \(100\) pés de cerca para fazer uma área de recreação retangular encostada na parede da sua casa. A parede da casa delimita um dos lados. Qual é a maior área possível (em pés quadrados)?
xmhint
xmhintPrecisamos maximizar a área, \(A\). Como \(100=2x+y\), segue que

\(y=100-2x\).

xmhintAgora expressamos a área como função de \(x\).

\(A(x)=\class{xm-answer}{\cssId{xm-answer-1}{\phantom{\rule{7em}{1.5em}}}}\cdot (100-2x)\)

xmhintPortanto, precisamos encontrar o máximo absoluto da função \(A\), dada por

\(A(x)=100\cdot \class{xm-answer}{\cssId{xm-answer-2}{\phantom{\rule{7em}{1.5em}}}}-2x^2\)

em seu domínio \([0,50]\).

xmhintPrecisamos encontrar todos os pontos críticos de \(A\) em \([0,50]\). Como

\(A'(x)=\class{xm-answer}{\cssId{xm-answer-3}{\phantom{\rule{7em}{1.5em}}}}-4x\),

segue que a função \(A\) tem seu único ponto crítico em \(x=\class{xm-answer}{\cssId{xm-answer-4}{\phantom{\rule{7em}{1.5em}}}}\).

xmhintPrecisamos calcular \(A\) nas extremidades e no ponto crítico.

\(A(0)=\class{xm-answer}{\cssId{xm-answer-5}{\phantom{\rule{7em}{1.5em}}}}\)

\(A(50)=\class{xm-answer}{\cssId{xm-answer-6}{\phantom{\rule{7em}{1.5em}}}}\)

\(A(25)=\class{xm-answer}{\cssId{xm-answer-7}{\phantom{\rule{7em}{1.5em}}}}\)

Agora comparamos esses três valores e determinamos o máximo absoluto de \(A\).

\[ \class{xm-answer}{\cssId{xm-answer-8}{\phantom{\rule{7em}{1.5em}}}} ft^2 \]