) has to be a local maximum and, therefore, it occurs at a critical point. So, we have to find all critical points of {{MATH_37}} on the interval {{MATH_38}}. Since {{MATH_39}} in order to find the critical points, we have to solve the equation {{MATH_40}} It follows that the only critical point of {{MATH_41}} is at {{MATH_42}}. We can make a sign chart for {{MATH_43}} on the interval {{MATH_44}}: {{CMD_45}} {{ENV_46}} {{CMD_47}}