First, compute {{MATH_61}} {{CMD_62}} The function {{MATH_63}} has {{MATH_64}} critical point(s). {{CMD_65}} The single critical point of {{MATH_66}} is located at {{MATH_67}} {{CMD_68}} Now compute {{MATH_69}} {{CMD_70}} Because the value of {{MATH_71}} is {{CMD_72}}{{CMD_73}}positive{{CMD_74}}{{CMD_75}}negative{{CMD_76}}{{CMD_77}}zero{{CMD_78}}{{CMD_79}}, the critical point the function {{MATH_80}} has at {{MATH_81}} is {{CMD_82}}{{CMD_83}}a local maximum{{CMD_84}}{{CMD_85}}a local minimum{{CMD_86}}{{CMD_87}}neither a local maximum nor a local minimum{{CMD_88}}{{CMD_89}}possibly a local maximum, a local minimum or neither{{CMD_90}}{{CMD_91}} by the second derivative test.