Now if we wanted to compute the area of {{MATH_7}} we could perform a substitution with {{MATH_8}}. In this case {{MATH_9}}. The lower bound is {{MATH_10}} and our upper bound is {{MATH_11}}. Making all these substitutions, we can rewrite our integral that computes the area of {{MATH_12}} as {{MATH_13}} which is exactly the integral that computes the area of {{MATH_14}}. Thus we see that {{MATH_15}} and {{MATH_16}} have the same area.