So, we have to find the (global) minimum of {{MATH_19}} on its domain, {{MATH_20}}. We have to find critical points of {{MATH_21}}. Therefore, we have to compute {{MATH_22}}. {{CMD_23}} {{CMD_24}} {{MATH_25}}. {{CMD_26}} {{CMD_27}} We have to find critical points of {{MATH_28}}. So, we have to solve the equation {{MATH_29}}. It follows that {{MATH_30}} has the only critical point {{MATH_31}}. {{CMD_32}} {{CMD_33}} Since {{MATH_34}}, it follows that {{MATH_35}} on {{MATH_36}} and that {{MATH_37}} on {{MATH_38}}. This means that {{MATH_39}} is decreasing on {{MATH_40}} and increasing on {{MATH_41}}. That means that the function {{MATH_42}} has both a local minimum and global minimum at {{MATH_43}}. {{CMD_44}}