Let {{MATH_34}} be the slope of the secant line through the points {{MATH_35}} and {{MATH_36}} (see figure above). Select the correct statement. {{CMD_37}} {{CMD_38}}{{MATH_39}}{{CMD_40}} {{CMD_41}}{{MATH_42}}{{CMD_43}} {{CMD_44}}{{MATH_45}}{{CMD_46}} {{CMD_47}}{{MATH_48}}{{CMD_49}} {{CMD_50}}{{MATH_51}}{{CMD_52}} {{CMD_53}}{{MATH_54}}{{CMD_55}} {{CMD_56}}{{MATH_57}}{{CMD_58}} {{CMD_59}}{{MATH_60}}{{CMD_61}} {{CMD_62}}{{MATH_63}}{{CMD_64}} {{CMD_65}}{{MATH_66}}{{CMD_67}} {{CMD_68}} {{CMD_69}} {{CMD_70}} Complete the statement below regarding the function {{MATH_71}} on the interval {{MATH_72}}. Select all correct choices. (Note, {{MATH_73}}, the slope of the secant line through the points {{MATH_74}} and {{MATH_75}}, was computed in the previous exercise.) STATEMENT: The Mean value theorem guarantees that there exists a point {{MATH_76}} in the open interval {{MATH_77}} such that {{CMD_78}} {{CMD_79}}{{MATH_80}}{{CMD_81}} {{CMD_82}}{{MATH_83}}{{CMD_84}} {{CMD_85}}{{MATH_86}}{{CMD_87}} {{CMD_88}}{{MATH_89}}{{CMD_90}} {{CMD_91}}{{MATH_92}}{{CMD_93}} {{CMD_94}}{{MATH_95}}{{CMD_96}} {{CMD_97}}{{MATH_98}}{{CMD_99}} {{CMD_100}}{{MATH_101}}{{CMD_102}} {{CMD_103}}{{MATH_104}}{{CMD_105}} {{CMD_106}}{{MATH_107}}{{CMD_108}} {{CMD_109}} {{CMD_110}}