First we consider {{MATH_3}}. We apply the mean value theorem to {{MATH_4}} on the interval {{MATH_5}} to find there exists a {{MATH_6}} with {{MATH_7}} Now we solve for {{MATH_8}} in the above expression to find {{MATH_9}} Since {{MATH_10}} we know that {{MATH_11}} Using this bound we find that {{MATH_12}}