The area approximation given by this Riemann Sum is an {{CMD_41}}{{CMD_42}}overestimate{{CMD_43}}{{CMD_44}}underestimate{{CMD_45}}{{CMD_46}} because {{CMD_47}} {{CMD_48}}the rectangles contain more area than is contained in the region.{{CMD_49}} {{CMD_50}}there is more area in the region than contained in the rectangles.{{CMD_51}} {{CMD_52}}it is impossible to tell.{{CMD_53}} {{CMD_54}}