Although the function {{MATH_29}} is continuous on its domain, its domain is an open, unbounded interval and the Extreme Value Theorem does not apply; there is no guarantee that the minimum even exists. But we don't give up! Our strategy will be to search for a critical point and check if the minimum is attained there. By solving the equation {{MATH_30}} we find that the point where {{MATH_31}} is the only critical point of {{MATH_32}}. Since {{MATH_33}} is positive when {{MATH_34}} is positive, there is a local minimum at the critical point, and hence a global minimum since there is only one critical point.