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To start, note that the Inverse Function Theorem assures us that this derivative actually exists. Recall {{MATH_27}} means that {{MATH_28}} and {{MATH_29}}. Implicitly differentiating with respect to {{MATH_30}} we obtain that {{ENV_31}} Recall the trig identity: {{MATH_32}}.{{CMD_33}} {{ENV_34}} Recall from above: {{MATH_35}}.{{CMD_36}} {{ENV_37}} {{COMMENT_38}} {{COMMENT_39}} {{COMMENT_40}} {{COMMENT_41}} {{COMMENT_42}} {{COMMENT_43}} {{COMMENT_44}} {{COMMENT_45}} {{COMMENT_46}} {{COMMENT_47}} {{COMMENT_48}} {{COMMENT_49}} {{COMMENT_50}} {{COMMENT_51}} {{COMMENT_52}} {{COMMENT_53}} {{COMMENT_54}} {{COMMENT_55}} {{COMMENT_56}} {{COMMENT_57}} {{COMMENT_58}} {{COMMENT_59}} {{COMMENT_60}} {{COMMENT_61}} {{COMMENT_62}} {{COMMENT_63}} {{COMMENT_64}} {{COMMENT_65}} {{COMMENT_66}} {{COMMENT_67}} {{COMMENT_68}} {{COMMENT_69}} {{COMMENT_70}} {{COMMENT_71}} {{COMMENT_72}} {{COMMENT_73}} {{COMMENT_74}} {{COMMENT_75}} {{COMMENT_76}} {{COMMENT_77}}

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