Consider the function {{MATH_233}} Does {{MATH_234}} have an inverse? If so, what is it? If not, attempt to restrict the domain of {{MATH_235}} and find an inverse on the restricted domain. {{CMD_236}} In this case {{MATH_237}} is not one-to-one. However, it is one-to-one on the interval {{MATH_238}}. Hence we can find an inverse of {{MATH_239}} on this interval. We plug {{MATH_240}} into {{MATH_241}} and write {{ENV_242}} Since the domain of {{MATH_243}} is {{MATH_244}}, we know that {{MATH_245}} is positive. This means we can take the square-root of each side of the equation to find that {{MATH_246}} {{CMD_247}} {{ENV_248}} {{COMMENT_249}} {{COMMENT_250}} {{COMMENT_251}} {{COMMENT_252}} {{CMD_253}} {{CMD_254}} {{CMD_255}} {{CMD_256}} Consider the graph of {{MATH_257}} below {{CMD_258}} {{ENV_259}} {{CMD_260}} Is the function {{MATH_261}} one-to-one on the interval {{MATH_262}}? {{CMD_263}} {{CMD_264}}yes{{CMD_265}} {{CMD_266}}no{{CMD_267}} {{CMD_268}} {{CMD_269}} Let {{MATH_270}} be the inverse function of {{MATH_271}} restricted to the domain {{MATH_272}}. {{CMD_273}} {{CMD_274}} Find the domain of {{MATH_275}}. {{CMD_276}} {{MATH_277}} {{CMD_278}} {{CMD_279}} Find the value of {{MATH_280}}. {{CMD_281}} {{MATH_282}} {{CMD_283}} {{CMD_284}} Choose the correct answer regarding {{MATH_285}}. {{CMD_286}} {{CMD_287}}{{MATH_288}}{{CMD_289}} {{CMD_290}}{{MATH_291}}{{CMD_292}} {{CMD_293}}{{MATH_294}} is not defined{{CMD_295}} {{CMD_296}} {{CMD_297}} {{CMD_298}} {{CMD_299}}